I can't imagine that he doesn't have secondary criteria, b/c that would mean he didn't foresee the possibility of 2 clans competing for 1st place to have same # of wins ... he's smarter than that
For examples, all it takes is 1 territory left in CW map, 2 clans tied for 1st place with both at exact same # of wins, same other clan (3rd place or lower) finishes a game that takes the last territory ending the season . . .
I can't imagine that he wouldn't have foreseen that
But maybe people are asking the wrong question; perhaps it's not "how do you determine the winning order?" (to which the answer is just refer to the order in the ongoing list) but rather how do you sort the clans into the ongoing list. The one we see on the CW map. It's likely just populating that view, and taking the order of clans from there to decide placement. They are obviously ordered primarily by # of wins, so what are the secondary, tertiary sort keys? And if there are none, then it is like getting a CW match before the randomness update was implemented, how they were ordered by WZ join date (actually account ID which correlates to WZ join date). But since CW winners are at clan level and not individual player level, it could literally be any aggregate field such as most # of points won at a clan level, or just the primary key from some other table involved in the join/query ... so maybe just the order clans appear in this list
https://www.warzone.com/Clans/List, which I think actually is sum of all points earned in the last ?month? (some period of time)
But as he doesn't know, it's likely NOT going to be some complicated active net new tiebreaker criteria like some "difficulty" factor to assess who got the harder matches that season such as sum of difference of CW ratings for each match, and the lowest (closest to 0 or lowest negative #) would be given the edge for higher placement (so for example, Cats beating ONE would be worth more than ONE beating Cats -- but only as pertains to breaking ties). He'd probably remember doing something like that.